A trader purchases a wrist watch and a pendul | vedclass

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Question

(C) Let the cost price $(CP)$ of the wrist watch be $Rs. x$.Then,the $CP$ of the pendulum is $Rs. (390 - x)$.Profit on the watch $= 10 \% 	ext{ of }

Vedclass · Accepted Answer

$110$

Vedclass · Answer

(C) Let the cost price $(CP)$ of the wrist watch be $Rs. x$.Then,the $CP$ of the pendulum is $Rs. (390 - x)$.Profit on the watch $= 10 \% 	ext{ of } x = 0.10x$.Profit on the pendulum $= 15 \% 	ext{ of } (390 - x) = 0.15(390 - x) = 58.5 - 0.15x$.Total profit $= 0.10x + 58.5 - 0.15x = 58.5 - 0.05x$.Given that the total profit is $Rs. 51.50$,we have:$58.5 - 0.05x = 51.50$$0.05x = 58.5 - 51.50 = 7.00$$x = \frac{7}{0.05} = 140$.So,the $CP$ of the wrist watch is $Rs. 140$.The $CP$ of the pendulum is $390 - 140 = Rs. 250$.The difference between the original prices is $250 - 140 = Rs. 110$.

$A$ trader purchases a wrist watch and a pendulum for $Rs. 390$. He sells them making a profit of $10 \%$ on the watch and $15 \%$ on the pendulum. He earns a total profit of $Rs. 51.50$. The difference between the original prices of the pendulum and the watch is equal to? (in $Rs.$)

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