A train 110 , m long is running with a speed | vedclass

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Question

(B) Since the man is running in the opposite direction to the train, the relative speed is the sum of their individual speeds.Relative speed $= 60 + 6

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(B) Since the man is running in the opposite direction to the train, the relative speed is the sum of their individual speeds.Relative speed $= 60 + 6 = 66 \, km/h$.To convert the speed from $km/h$ to $m/s$, multiply by $\frac{5}{18}$:Relative speed $= 66 	imes \frac{5}{18} = \frac{11 	imes 5}{3} = \frac{55}{3} \, m/s$.The distance to be covered to pass the man is equal to the length of the train, which is $110 \, m$.Time taken $= \frac{	ext{Distance}}{	ext{Relative Speed}} = \frac{110}{\frac{55}{3}} = 110 	imes \frac{3}{55} = 2 	imes 3 = 6 \, seconds$.

$A$ train $110 \, m$ long is running with a speed of $60 \, km/h$. In what time will it pass a man who is running at $6 \, km/h$ in the direction opposite to that in which the train is going? (in $seconds$)

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