A train of 320 , m crosses a platform in 24 , | vedclass

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(D) Step $1$: Convert the speed of the train from $km/h$ to $m/s$.Speed $= 120 	imes \frac{5}{18} = \frac{600}{18} = \frac{100}{3} \, m/s$.Step $2$:

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(D) Step $1$: Convert the speed of the train from $km/h$ to $m/s$.Speed $= 120 	imes \frac{5}{18} = \frac{600}{18} = \frac{100}{3} \, m/s$.Step $2$: Calculate the length of the platform $(x)$.Total distance covered by the train = Length of train + Length of platform = $320 + x$.Using the formula $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$:$320 + x = \frac{100}{3} 	imes 24$$320 + x = 100 	imes 8 = 800$$x = 800 - 320 = 480 \, m$.Step $3$: Calculate the speed of the man.The man crosses the platform $(480 \, m)$ in $4 \, min$.Time in seconds $= 4 	imes 60 = 240 \, s$.Speed of man $= \frac{	ext{Distance}}{	ext{Time}} = \frac{480}{240} = 2.0 \, m/s$.

$A$ train of $320 \, m$ crosses a platform in $24 \, s$ at a speed of $120 \, km/h$. $A$ man crosses the same platform in $4 \, min$. What is the speed of the man in $m/s$?

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