A transformer has 100 turns in the primary co | vedclass

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(C) Given: Primary turns $N_1 = 100$, Primary current $I_1 = 8$ $A$, Input power $P_{in} = 1000$ $W$, Secondary voltage $V_2 = 500$ $V$.
First, calcu

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(C) Given: Primary turns $N_1 = 100$, Primary current $I_1 = 8$ $A$, Input power $P_{in} = 1000$ $W$, Secondary voltage $V_2 = 500$ $V$.
First, calculate the primary voltage $V_1$ using $P_{in} = V_1 I_1$:
$1000 = V_1 	imes 8 \Rightarrow V_1 = 125$ $V$.
For an ideal transformer, the ratio of turns is equal to the ratio of voltages:
$\frac{N_2}{N_1} = \frac{V_2}{V_1}$
$\frac{N_2}{100} = \frac{500}{125}$
$\frac{N_2}{100} = 4$
$N_2 = 400$ turns.

$A$ transformer has $100$ turns in the primary coil and carries $8$ $A$ current. If input power is $1$ $kW$, the number of turns in the secondary coil to have $500$ $V$ output will be

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