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(C) The current gain $\beta$ in common emitter configuration is related to $\alpha$ by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Substituting $\

Vedclass · Accepted Answer

$26$

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(C) The current gain $\beta$ in common emitter configuration is related to $\alpha$ by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Substituting $\alpha = 0.96$,we get $\beta = \frac{0.96}{1 - 0.96} = \frac{0.96}{0.04} = 24$.The collector current $I_{C}$ is determined by the voltage drop across the collector resistor $R_C = 800 \ \Omega$:$I_{C} = \frac{V_{drop}}{R_C} = \frac{0.5 \ V}{800 \ \Omega} = 0.000625 \ A = 0.625 	imes 10^{-3} \ A$.The base current $I_{B}$ is given by $I_{B} = \frac{I_{C}}{\beta}$.Substituting the values,$I_{B} = \frac{0.625 	imes 10^{-3} \ A}{24} \approx 0.02604 	imes 10^{-3} \ A = 26.04 	imes 10^{-6} \ A$.Thus,the base current is approximately $26 \ \mu A$.

$A$ transistor is connected in common emitter $(CE)$ configuration. The collector supply is $8 \ V$ and the voltage drop across a resistor of $800 \ \Omega$ in the collector circuit is $0.5 \ V$. If the current gain factor $\alpha$ is $0.96$,find the base current in $\mu A$.

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