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(D) The change in base current is $\Delta I_B = 150 \, \mu A - 100 \, \mu A = 50 \, \mu A = 50 	imes 10^{-6} \, A$.The change in collector current is

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) The change in base current is $\Delta I_B = 150 \, \mu A - 100 \, \mu A = 50 \, \mu A = 50 	imes 10^{-6} \, A$.The change in collector current is $\Delta I_C = 10 \, mA - 5 \, mA = 5 \, mA = 5 	imes 10^{-3} \, A$.The current gain $\beta$ in common emitter configuration is defined as the ratio of the change in collector current to the change in base current:$\beta = \frac{\Delta I_C}{\Delta I_B} = \frac{5 	imes 10^{-3} \, A}{50 	imes 10^{-6} \, A} = \frac{5000 	imes 10^{-6}}{50 	imes 10^{-6}} = 100$.Therefore,the current gain $\beta$ is $100$.

$A$ transistor is operated in common emitter configuration at a constant collector voltage $V_C = 1.5 \, V$ such that a change in the base current from $100 \, \mu A$ to $150 \, \mu A$ produces a change in the collector current from $5 \, mA$ to $10 \, mA$. The current gain $\beta$ is:

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