A transmitter transmits a power of 10, kW whe | vedclass

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(B) The total transmitted power $P_t$ in amplitude modulation is given by the formula: $P_t = P_c \left( 1 + \frac{m_a^2}{2} \right)$,where $P_c$ is t

Vedclass · Accepted Answer

$8.89$

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(B) The total transmitted power $P_t$ in amplitude modulation is given by the formula: $P_t = P_c \left( 1 + \frac{m_a^2}{2} \right)$,where $P_c$ is the carrier power and $m_a$ is the modulation index.Given: $P_t = 10\, kW$ and $m_a = 50\% = 0.5$.Substituting the values: $10 = P_c \left( 1 + \frac{(0.5)^2}{2} \right)$.$10 = P_c \left( 1 + \frac{0.25}{2} \right) = P_c (1 + 0.125) = 1.125 P_c$.$P_c = \frac{10}{1.125} \approx 8.89\, kW$.

$A$ transmitter transmits a power of $10\, kW$ when modulation is $50\%$. The power of the carrier wave is.......$kW$.

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