A triangular pulse moving at 2 cm/s on a rop | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The wave pulse moves at a speed $v_w = 2 \ cm/s$. At $t = 0$,the trailing edge of the pulse is at a distance of $2 \ cm$ from the free end. In $t

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) The wave pulse moves at a speed $v_w = 2 \ cm/s$. At $t = 0$,the trailing edge of the pulse is at a distance of $2 \ cm$ from the free end. In $t = \frac{3}{4} \ s$,the pulse travels a distance $d = v_w 	imes t = 2 	imes \frac{3}{4} = 1.5 \ cm$. Since the trailing edge was $2 \ cm$ away,after $0.75 \ s$,the trailing edge is at $2 - 1.5 = 0.5 \ cm$ from the free end. This means the free end is currently located on the trailing slope of the triangular pulse. The slope of the trailing edge is $m = \frac{	ext{height}}{	ext{base}} = \frac{1 \ cm}{1 \ cm} = 1$. For a wave pulse,the particle velocity $v_p$ is given by $v_p = -v_w 	imes 	ext{slope}$. Since the trailing edge has a negative slope (relative to the direction of motion),the particle velocity at the free end is $v_p = -2 	imes (-1) = 2 \ cm/s$.

$A$ triangular pulse moving at $2 \ cm/s$ on a rope approaches an end at which it is free to slide on a vertical pole. What is the particle speed at the free end at $\frac{3}{4} \ s$ from the instant shown? (in $cm/s$)

Similar Questions

$A$ plane wave is represented by $x = 1.2 \sin(314t + 12.56y)$,where $x$ and $y$ are distances measured in meters and $t$ is time in seconds. This wave has:

$A$ wave equation which gives the displacement along the $Y$ direction is given by the equation $y = 10^4 \sin(60t + 2x)$,where $x$ and $y$ are in metres and $t$ is time in seconds. This represents a wave:

The equation of a transverse wave travelling on a rope is given by $y = 10\sin \pi (0.01x - 2.00t)$ where $y$ and $x$ are in $cm$ and $t$ is in $seconds$. The maximum transverse speed of a particle in the rope is about .... $cm/s$.

The two waves represented by $y_1 = a \sin(\omega t)$ and $y_2 = b \cos(\omega t)$ have a phase difference of

The displacement $y$ of a particle in a medium can be expressed as: $y = 10^{-6} \sin(100t + 20x + \pi/4) \ m$,where $t$ is in seconds and $x$ is in meters. The speed of the wave is ... $m/s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module