A TV transmitting antenna is 98,m high and th | vedclass

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(B) Given: Height of transmitting antenna $h_T = 98\,m = 0.098\,km$. Height of receiving antenna $h_R = 0\,m$. Radius of the earth $R = 6400\,km$.The

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$3942$

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(B) Given: Height of transmitting antenna $h_T = 98\,m = 0.098\,km$. Height of receiving antenna $h_R = 0\,m$. Radius of the earth $R = 6400\,km$.The maximum line-of-sight distance $d$ is given by the formula $d = \sqrt{2 R h_T} + \sqrt{2 R h_R}$.Since $h_R = 0$,the formula simplifies to $d = \sqrt{2 R h_T}$.Substituting the values: $d = \sqrt{2 	imes 6400 	imes 0.098} = \sqrt{12800 	imes 0.098} = \sqrt{1254.4} \approx 35.417\,km$.The surface area $A$ covered by the antenna is given by $A = \pi d^2$.$A = 3.14159 	imes (35.417)^2 \approx 3.14159 	imes 1254.4 \approx 3941.07\,km^2$.Rounding to the nearest integer,the area is approximately $3942\,km^2$.

$A$ $TV$ transmitting antenna is $98\,m$ high and the receiving antenna is at the ground level. If the radius of the earth is $6400\,km$,the surface area covered by the transmitting antenna is approximately $.........\,km^2$

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