A uniform cubical block is subjected to volum | vedclass

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(C) The volume of a cube is given by $V = a^3$,where $a$ is the side length.Taking the logarithmic derivative,we get $\frac{\Delta V}{V} = 3 \frac{\De

Vedclass · Accepted Answer

$0.06$

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(C) The volume of a cube is given by $V = a^3$,where $a$ is the side length.Taking the logarithmic derivative,we get $\frac{\Delta V}{V} = 3 \frac{\Delta a}{a}$.Given that the side decreases by $2 \%$,we have $\frac{\Delta a}{a} = -0.02$.Substituting this value into the expression for volumetric strain:$\frac{\Delta V}{V} = 3 	imes (-0.02) = -0.06$.The bulk strain is defined as the magnitude of the volumetric strain,which is $|\frac{\Delta V}{V}| = 0.06$.

$A$ uniform cubical block is subjected to volumetric compression,which decreases its each side by $2 \%$. The Bulk strain produced in it is ............

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