$A$ uniform electric field $E = (8m/e) \text{ V/m}$ is created between two parallel plates of length $1 \text{ m}$ as shown in the figure (where $m = \text{mass of electron}$ and $e = \text{charge of electron}$). An electron enters the field symmetrically between the plates with a speed of $2 \text{ m/s}$. The angle of the deviation $(\theta)$ of the path of the electron as it comes out of the field will be:

• A
  $\tan^{-1}(4)$
• B
  $\tan^{-1}(2)$
• C
  $\tan^{-1}(1/3)$
• D
  $\tan^{-1}(3)$