A vehicle of 100, kg is moving with a velocit | vedclass

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(A) Given: Mass $m = 100\, kg$,Initial velocity $u = 5\, m/s$,Final velocity $v = 0\, m/s$,Time $t = \frac{1}{10}\, s = 0.1\, s$.According to Newton's

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$5000$

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(A) Given: Mass $m = 100\, kg$,Initial velocity $u = 5\, m/s$,Final velocity $v = 0\, m/s$,Time $t = \frac{1}{10}\, s = 0.1\, s$.According to Newton's Second Law of Motion,the force required is given by $F = m 	imes a$,where $a$ is the acceleration (or deceleration).The acceleration is $a = \frac{v - u}{t} = \frac{0 - 5}{0.1} = -50\, m/s^2$.The magnitude of the force required to stop the vehicle is $F = |m 	imes a| = 100\, kg 	imes 50\, m/s^2 = 5000\, N$.

$A$ vehicle of $100\, kg$ is moving with a velocity of $5\, m/s$. To stop it in $\frac{1}{10}\, s$,the required force in the opposite direction is ........... $N$.

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