A vertical bar magnet is dropped from a posit | vedclass

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(C) According to Lenz's Law,the direction of the induced current in a coil is such that it opposes the change in magnetic flux that produced it.In fig

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$a_1 < g, a_2 < g$

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(C) According to Lenz's Law,the direction of the induced current in a coil is such that it opposes the change in magnetic flux that produced it.In fig-$I$,as the bar magnet falls towards the fixed coil,the magnetic flux through the coil increases. The coil induces a current that creates a magnetic field opposing the motion of the magnet. This creates an upward repulsive force on the magnet,causing its acceleration $a_1$ to be less than the acceleration due to gravity $g$ $(a_1 In fig-$II$,the magnet is fixed and the coil is dropped. As the coil falls towards the magnet,the magnetic flux through the coil increases. Again,by Lenz's Law,the induced current in the coil creates a magnetic field that opposes the relative motion. This results in an upward magnetic force on the falling coil,which opposes its downward motion due to gravity. Therefore,the acceleration $a_2$ of the coil is also less than the acceleration due to gravity $g$ $(a_2 Thus,in both cases,the acceleration is less than $g$.

$A$ vertical bar magnet is dropped from a position on the axis of a fixed metallic coil as shown in fig-$I$. In fig-$II$,the magnet is fixed and a horizontal coil is dropped. If the acceleration of the magnet and the coil are $a_1$ and $a_2$ respectively,then:

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