A vessel contains 1 mole of O_2 gas (molar ma | vedclass

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(C) The ideal gas equation is given by $PV = nRT$,where $P$ is pressure,$V$ is volume,$n$ is the number of moles,$R$ is the universal gas constant,and

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$2P$

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(C) The ideal gas equation is given by $PV = nRT$,where $P$ is pressure,$V$ is volume,$n$ is the number of moles,$R$ is the universal gas constant,and $T$ is the absolute temperature.For the $O_2$ gas vessel:$P_1 = P, V_1 = V, n_1 = 1, T_1 = T$So,$PV = (1)RT = RT$  --- (Equation $1$)For the $He$ gas vessel:$P_2 = ?, V_2 = V, n_2 = 1, T_2 = 2T$Using the ideal gas equation: $P_2 V = n_2 R T_2$$P_2 V = (1)R(2T) = 2RT$  --- (Equation $2$)Dividing Equation $2$ by Equation $1$:$P_2 V / PV = 2RT / RT$$P_2 / P = 2$$P_2 = 2P$Therefore,the pressure of the $He$ gas is $2P$.

$A$ vessel contains $1$ mole of $O_2$ gas (molar mass $32$) at a temperature $T$. The pressure of the gas is $P$. An identical vessel containing $1$ mole of $He$ gas (molar mass $4$) at a temperature $2T$ has a pressure of:

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