A vessel is in the form of a hollow hemispher | vedclass

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(B) It can be observed that the radius $(r)$ of the cylindrical part and the hemispherical part is the same (i.e.,$7 \, cm$).Height of the hemispheric

Vedclass · Accepted Answer

$572$

Vedclass · Answer

(B) It can be observed that the radius $(r)$ of the cylindrical part and the hemispherical part is the same (i.e.,$7 \, cm$).Height of the hemispherical part = Radius $= 7 \, cm$.Height of the cylindrical part $(h) = 13 - 7 = 6 \, cm$.Inner surface area of the vessel = $CSA$ of the cylindrical part + $CSA$ of the hemispherical part.Inner surface area $= 2 \pi r h + 2 \pi r^2 = 2 \pi r (h + r)$.Inner surface area $= 2 	imes \frac{22}{7} 	imes 7 	imes (6 + 7)$.Inner surface area $= 44 	imes 13 = 572 \, cm^2$.

$A$ vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is $14 \, cm$ and the total height of the vessel is $13 \, cm$. Find the inner surface area of the vessel. [Use $\pi = \frac{22}{7}$] (in $, cm^2$)

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