A wave of frequency 500 , Hz has a velocity o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given frequency $n = 500 \, Hz$ and velocity $v = 360 \, m/s$.First,calculate the wavelength $\lambda$ using the formula $v = n\lambda$:$\lambda =

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(B) Given frequency $n = 500 \, Hz$ and velocity $v = 360 \, m/s$.First,calculate the wavelength $\lambda$ using the formula $v = n\lambda$:$\lambda = \frac{v}{n} = \frac{360}{500} = 0.72 \, m$.The phase difference $\phi$ is given as $60^o$. Converting this to radians:$\phi = 60^o 	imes \frac{\pi}{180^o} = \frac{\pi}{3} \, 	ext{radians}$.The path difference $\Delta x$ is related to the phase difference $\phi$ by the formula:$\Delta x = \frac{\lambda}{2\pi} 	imes \phi$.Substituting the values:$\Delta x = \frac{0.72}{2\pi} 	imes \frac{\pi}{3} = \frac{0.72}{6} = 0.12 \, m$.Converting the distance to centimeters:$\Delta x = 0.12 	imes 100 = 12 \, cm$.

$A$ wave of frequency $500 \, Hz$ has a velocity of $360 \, m/s$. The distance between two nearest points $60^o$ out of phase is .... $cm$.

Similar Questions

Write the definition,unit,and dimensional formula of amplitude.

The distance between two consecutive points with phase difference of $45^{\circ}$ in a wave of frequency $300 \text{ Hz}$ is $4.0 \text{ m}$. The velocity of the travelling wave is (in $\text{km/s}$):

The equation of wave motion is $Y = 6 \sin (12\pi t - 0.02\pi x + \pi/3)$ where $x$ is in metre and time in second. The velocity of the wave is (in $\text{ m/s}$)

The wave described by $y = 0.25 \sin(10\pi x - 2\pi t)$,where $x$ and $y$ are in $meters$ and $t$ in $seconds$,is a wave travelling along:

The phase difference between two points separated by $1 \ m$ in a wave of frequency $120 \ Hz$ is $90^o$. The wave velocity is .... $m/s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module