A weak acid HX has the dissociation constant | vedclass

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(B) $NaX$ is a salt of a weak acid and a strong base.For such a salt,the degree of hydrolysis $h$ is given by the formula:$h = \sqrt{\frac{K_w}{K_a

Vedclass · Accepted Answer

$0.01$

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(B) $NaX$ is a salt of a weak acid and a strong base.For such a salt,the degree of hydrolysis $h$ is given by the formula:$h = \sqrt{\frac{K_w}{K_a 	imes C}}$Given:$K_w = 10^{-14}$$K_a = 1 	imes 10^{-5}$$C = 0.1 	ext{ } M$Substituting the values:$h = \sqrt{\frac{10^{-14}}{10^{-5} 	imes 0.1}} = \sqrt{\frac{10^{-14}}{10^{-6}}} = \sqrt{10^{-8}} = 10^{-4}$Percentage hydrolysis $= h 	imes 100 = 10^{-4} 	imes 100 = 0.01 \%$

$A$ weak acid $HX$ has the dissociation constant $1 \times 10^{-5} \text{ } M$. It forms a salt $NaX$ on reaction with alkali. The percentage hydrolysis of $0.1 \text{ } M$ solution of $NaX$ is ............... $\%$

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