A weak acid HX (K_a = 10^{-5}) on reaction wi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For the salt $NaX$,which is a salt of a weak acid and a strong base,the hydrolysis reaction is:$X^{-} + H_2O \rightleftharpoons HX + OH^{-}$The hy

Vedclass · Accepted Answer

$0.01$

Vedclass · Answer

(B) For the salt $NaX$,which is a salt of a weak acid and a strong base,the hydrolysis reaction is:$X^{-} + H_2O ightleftharpoons HX + OH^{-}$The hydrolysis constant $K_h$ is given by $K_h = \frac{K_w}{K_a} = \frac{10^{-14}}{10^{-5}} = 10^{-9}$.The degree of hydrolysis $h$ is given by the formula $h = \sqrt{\frac{K_h}{C}}$,where $C = 0.1 \ M$.Substituting the values:$h = \sqrt{\frac{10^{-9}}{0.1}} = \sqrt{10^{-8}} = 10^{-4}$.The percentage of hydrolysis is calculated as:$\% h = h 	imes 100 = 10^{-4} 	imes 100 = 10^{-2} = 0.01 \ \%$.

$A$ weak acid $HX$ $(K_a = 10^{-5})$ on reaction with $NaOH$ gives $NaX$. For $0.1 \ M$ aqueous solution of $NaX$,the $\%$ hydrolysis is $....... \ \%$.

Similar Questions

The aqueous solution of $FeCl_3$ is acidic due to

The hydrolysis constant of $0.1 \ M$ ammonium chloride is $2.5 \times 10^{-10}$. Its degree of hydrolysis is......

Calculate the $pH$ of a $0.018 \, M$ sodium acetate solution,given its $K_a = 1.8 \times 10^{-5}$. (in $.5$)

Hydrolysis of sodium acetate will give:

$A$ solution of $MgCl_2$ in water has $pH$:

Vedclass Test Series

Exam Paper Generator

Online Exam Module