A wheel has an angular acceleration of 3.0, r | vedclass

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(A) Given:Angular acceleration,$\alpha = 3.0\, rad/s^2$Initial angular velocity,$\omega_i = 2.00\, rad/s$Time,$t = 2\, s$Using the kinematic equation

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$10$

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(A) Given:Angular acceleration,$\alpha = 3.0\, rad/s^2$Initial angular velocity,$\omega_i = 2.00\, rad/s$Time,$t = 2\, s$Using the kinematic equation for rotational motion:$	heta = \omega_i t + \frac{1}{2} \alpha t^2$Substituting the values:$	heta = (2.00)(2) + \frac{1}{2}(3.0)(2)^2$$	heta = 4 + \frac{1}{2}(3.0)(4)$$	heta = 4 + 6 = 10\, rad$Thus,the wheel has rotated through an angle of $10\, radians$.

$A$ wheel has an angular acceleration of $3.0\, rad/s^2$ and an initial angular speed of $2.00\, rad/s$. In a time of $2\, s$,it has rotated through an angle (in radians) of:

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