$A$ wheel with ten metallic spokes,each $0.50 \ m$ long,is rotated with a speed of $120 \ rev/min$ in a plane normal to the earth's magnetic field at the place. If the magnitude of the field is $0.4 \ G$,the induced $e.m.f.$ between the axle and the rim of the wheel is equal to:
- A$1.256 \times 10^{-3} \ V$
- B$6.28 \times 10^{-4} \ V$
- C$1.256 \times 10^{-4} \ V$
- D$6.28 \times 10^{-5} \ V$
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