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(B) $pH$ of $9$ indicates that the solution is basic.$NH_4NO_3$ is a salt of a strong acid $(HNO_3)$ and a weak base $(NH_4OH)$,which results in an ac

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$CH_3COONa$

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(B) $pH$ of $9$ indicates that the solution is basic.$NH_4NO_3$ is a salt of a strong acid $(HNO_3)$ and a weak base $(NH_4OH)$,which results in an acidic solution $(pH $CH_3COONa$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$,which undergoes anionic hydrolysis to produce a basic solution $(pH > 7)$.$CH_3COONH_4$ is a salt of a weak acid and a weak base,which results in a nearly neutral solution $(pH \approx 7)$.$CaCO_3$ is insoluble in water.Therefore,the correct salt is $CH_3COONa$.

$A$ white salt is readily soluble in water and gives a colourless solution with a $pH$ of about $9$. The salt would be

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