A wind with speed 40,m/s blows parallel to th | vedclass

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(B) According to Bernoulli's principle,the pressure above the roof decreases as the wind speed increases.The pressure difference $\Delta P$ between th

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$2.4 	imes 10^5\,N,$ upwards

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(B) According to Bernoulli's principle,the pressure above the roof decreases as the wind speed increases.The pressure difference $\Delta P$ between the inside and outside of the roof is given by $\Delta P = \frac{1}{2} ho V^2$.Given: $ho = 1.2\,kg/m^3$,$V = 40\,m/s$,and $A = 250\,m^2$.$\Delta P = \frac{1}{2} 	imes 1.2 	imes (40)^2 = 0.6 	imes 1600 = 960\,Pa$.The force exerted on the roof is $F = \Delta P 	imes A$.$F = 960 	imes 250 = 240,000\,N = 2.4 	imes 10^5\,N$.Since the pressure outside is lower than the pressure inside,the net force acts in the upward direction.

$A$ wind with speed $40\,m/s$ blows parallel to the roof of a house. The area of the roof is $250\,m^2.$ Assuming that the pressure inside the house is atmospheric pressure,the force exerted by the wind on the roof and the direction of the force will be $(\rho_{air} = 1.2\,kg/m^3)$

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