A wire is looped in the form of a circle of r | vedclass

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(B) The perimeter of the circle is equal to the circumference,which is $2 \pi r$.Given $r = 28\, cm$,the circumference is $2 	imes \frac{22}{7} 	ime

Vedclass · Accepted Answer

$44 \sqrt{2}\, cm$

Vedclass · Answer

(B) The perimeter of the circle is equal to the circumference,which is $2 \pi r$.Given $r = 28\, cm$,the circumference is $2 	imes \frac{22}{7} 	imes 28 = 176\, cm$.Since the wire is bent into a square,the perimeter of the square is equal to the circumference of the circle.Let $a$ be the side of the square. Then $4a = 176\, cm$,which gives $a = 44\, cm$.The diagonal of a square is given by the formula $d = a \sqrt{2}$.Substituting the value of $a$,we get $d = 44 \sqrt{2}\, cm$.

$A$ wire is looped in the form of a circle of radius $28\, cm$. It is bent again into a square form. What will be the length of the diagonal of the largest square possible thus?

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