A wire of length 10 cm and radius sqrt{7} ti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a meter bridge,the balance condition is given by $\frac{P}{Q} = \frac{l_1}{l_2}$,where $P$ is the resistance in the left gap,$Q$ is the resist

Vedclass · Accepted Answer

$66$

Vedclass · Answer

(C) For a meter bridge,the balance condition is given by $\frac{P}{Q} = \frac{l_1}{l_2}$,where $P$ is the resistance in the left gap,$Q$ is the resistance in the right gap,$l_1 = 60 \ cm$,and $l_2 = 100 - 60 = 40 \ cm$.Given $P = 4.5 \ \Omega$,we have $\frac{4.5}{Q} = \frac{60}{40} = 1.5$.Thus,$Q = \frac{4.5}{1.5} = 3 \ \Omega$.The resistance of the wire is given by $Q = \frac{ho L}{A} = \frac{ho L}{\pi r^2}$,where $L = 10 \ cm = 0.1 \ m$ and $r = \sqrt{7} 	imes 10^{-4} \ m$.Substituting the values: $3 = \frac{ho 	imes 0.1}{\pi 	imes (\sqrt{7} 	imes 10^{-4})^2} = \frac{ho 	imes 0.1}{\pi 	imes 7 	imes 10^{-8}}$.Solving for $ho$: $ho = \frac{3 	imes \pi 	imes 7 	imes 10^{-8}}{0.1} = 210 \pi 	imes 10^{-8} \ \Omega \ m$.Using $\pi \approx 3.14$,$ho = 210 	imes 3.14 	imes 10^{-8} = 659.4 	imes 10^{-8} \approx 66 	imes 10^{-7} \ \Omega \ m$.Therefore,$R = 66$.

Similar Questions

In a meter bridge experiment,when resistance $X$ is in the left gap and $Y$ is in the right gap,the null point is found at $20 \ cm$ from the left end. If $X < Y$,what will be the new position of the null point from the same end if a resistance of $4X$ is placed in the left gap instead of $X$?

In a metre bridge experiment, the balance point is obtained if the gaps are closed by $2 \text{ } \Omega$ and $3 \text{ } \Omega$. $A$ shunt of $X \text{ } \Omega$ is added to $3 \text{ } \Omega$ resistor to shift the balancing point by $22.5 \text{ cm}$. The value of $X$ is

The experimental setup of a meter bridge is shown in the figure. If the null deflection point of the galvanometer is at distance $x$ from end $A$,what will be the new null point if the radius of the wire $AB$ is doubled?

Vedclass Test Series

Exam Paper Generator

Online Exam Module