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(C) Let the $X$ chromosome carrying the genes for haemophilia and colour blindness be denoted as $X^{hc}$. The normal $X$ chromosome is $X$. The woman

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$50\%$ haemophilic colourblind sons and $50\%$ normal sons

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(C) Let the $X$ chromosome carrying the genes for haemophilia and colour blindness be denoted as $X^{hc}$. The normal $X$ chromosome is $X$. The woman's genotype is $X^{hc}X$. The normal man's genotype is $XY$.Cross: $X^{hc}X 	imes XY$Gametes: $(X^{hc}, X)$ and $(X, Y)$Progeny genotypes: $X^{hc}X$ (carrier daughter),$X^{hc}Y$ (haemophilic and colourblind son),$XX$ (normal daughter),$XY$ (normal son).Thus,$50\%$ of the sons will be haemophilic and colourblind,and $50\%$ of the sons will be normal.

$A$ woman carrying two genes for haemophilia and one gene for colour blindness on one of her $X$ chromosomes marries a normal man. What will be the phenotype of the progeny?

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