(C) The total mass of the system is $M = 5 \, kg + 25 \, kg = 30 \, kg$.The downward force due to gravity is $W = Mg = 30 \times 9.8 = 294 \, N$.Let $

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(C) The total mass of the system is $M = 5 \, kg + 25 \, kg = 30 \, kg$.The downward force due to gravity is $W = Mg = 30 \times 9.8 = 294 \, N$.Let $N$ be the normal reaction force exerted by the floor on the system. According to Newton's second law for the downward motion:$Mg - N = Ma$Substituting the values:$294 - N = 30 \times 0.1$$294 - N = 3$$N = 294 - 3 = 291 \, N$.By Newton's third law, the action force of the system on the floor is equal to the normal reaction force $N$, which is $291 \, N$.

Class 11 Physics Laws of Motion Apparent weight and Pseudo Force

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$A$ wooden block of mass $5 \, kg$ rests on a soft horizontal floor. When an iron cylinder of mass $25 \, kg$ is placed on top of the block, the floor yields and the block and the cylinder together move down with an acceleration of $0.1 \, m/s^2$. The action force of the system on the floor is equal to: (in $N$)

JEE MAIN 2024 All JEE MAIN

A
$297$
B
$294$
C
$291$
D
$196$

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$A$ spring balance is attached to the ceiling of a lift. $A$ man hangs his bag on the spring and the spring balance reads $49 \,N$, when the lift is stationary. If the lift moves downward with an acceleration of $5 \,m/s^2$, the reading of the spring balance will be $(g = 9.8 \,m/s^2)$. (in $\,N$)

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