A word consists of 11 letters in which there | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Total number of letters = $11$.Number of consonants = $7$.Number of vowels = $4$.We need to choose $2$ letters out of $11$. The total number of wa

Vedclass · Accepted Answer

$\frac{21}{55}$

Vedclass · Answer

(B) Total number of letters = $11$.Number of consonants = $7$.Number of vowels = $4$.We need to choose $2$ letters out of $11$. The total number of ways to choose $2$ letters is given by $^{11}C_2 = \frac{11 	imes 10}{2 	imes 1} = 55$.The number of ways to choose $2$ consonants out of $7$ is given by $^7C_2 = \frac{7 	imes 6}{2 	imes 1} = 21$.The probability that both chosen letters are consonants is the ratio of the number of favorable outcomes to the total number of outcomes.Required probability = $\frac{^7C_2}{^{11}C_2} = \frac{21}{55}$.

$A$ word consists of $11$ letters in which there are $7$ consonants and $4$ vowels. If $2$ letters are chosen at random,then the probability that both of them are consonants is:

Similar Questions

Out of $40$ consecutive natural numbers,two are chosen at random. The probability that the sum of the numbers is odd is:

$A$ binary number is made up of $16$ bits. The probability of an incorrect bit appearing is $p$ and the errors in different bits are independent of one another. The probability of forming an incorrect number is

Find the probability of a $4$ turning up at least once in two tosses of a fair die.

An urn contains $25$ balls numbered $1$ to $25$. Suppose an odd number is considered a 'success'. If $2$ balls are drawn from the urn with replacement,find the probability of getting at least $2$ successes.

$4$ coins are tossed once. Find the probability of getting exactly $2$ tails.

Vedclass Test Series

Exam Paper Generator

Online Exam Module