$A$ word consists of $11$ letters in which there are $7$ consonants and $4$ vowels. If $2$ letters are chosen at random,then the probability that both of them are consonants is:
- A$\frac{5}{11}$
- B$\frac{21}{55}$
- C$\frac{4}{11}$
- DNone of these
Explore More
Similar Questions
$A$ three-digit number is formed by using the digits $1, 2, 3,$ and $4$ without repetition. The probability that the number is divisible by $3$ is:
Medium
View SolutionIf $4$ boys and $3$ girls are standing in a row for an interview,what is the probability that they stand in alternating positions?
Medium
View Solution$A$ board has $16$ squares arranged in a $4 \times 4$ grid. Out of these $16$ squares,two squares are chosen at random. The probability that they have no side in common is:
Out of $13$ applicants for a job,$5$ are women and $8$ are men. Two persons are to be selected for the job. What is the probability that at least one woman is selected?
Difficult
View Solution$A$ basket contains $3$ mangoes and $3$ apples. If two fruits are selected at random,what is the probability of getting one mango and one apple?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo