A Young's double slit experiment uses a monoc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In Young's double slit experiment,the path difference between the two waves reaching a point on the screen is given by $\Delta x = d \sin 	heta \

Vedclass · Accepted Answer

straight line

Vedclass · Answer

(A) In Young's double slit experiment,the path difference between the two waves reaching a point on the screen is given by $\Delta x = d \sin 	heta \approx d 	an 	heta = d(y/D)$.For bright fringes,the path difference is $n\lambda$,so $d(y/D) = n\lambda$,which implies $y = (n\lambda D)/d$.Since $y$ is constant for a given order $n$,the fringes appear as straight lines parallel to the slits on the screen.Therefore,the shape of the interference fringes is a straight line.

$A$ Young's double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is

Similar Questions

Most of the endangered species are the victims of

The value of $c$ in the Lagrange's mean value theorem for $f(x)=\sqrt{x-2}$ in the interval $[2,6]$ is

Hydrolysis of sucrose with dilute aqueous sulphuric acid yields

An object $1\;cm$ tall is placed $4\;cm$ in front of a mirror. In order to produce an upright image of $3\;cm$ height,one needs a:

If $2x + 3y = 5$ is the perpendicular bisector of the line segment joining the points $A\left(1, \frac{1}{3}\right)$ and $B$,then $B$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module