$A$ Zener diode is specified as having a breakdown voltage of $9.1 \;V$,with a maximum power dissipation of $364 \;mW$. What is the maximum current $(mA)$ the diode can handle?

The Zener diode has a breakdown voltage $V_{z} = 30\, V$. The current passing through the diode for the following circuit is $\ldots \ldots \ldots \,mA.$

In the circuit diagram shown in the figure,the current through the zener diode is (in $mA$)

$A$ Zener diode with a breakdown voltage of $15 \ V$ is used as a voltage regulator. In the circuit shown,the current flowing through the Zener diode is ...... $mA$.

$A$ Zener diode of breakdown voltage $V_{Z} = 8\,V$ and maximum Zener current $I_{ZM} = 10\,mA$ is subjected to an input voltage $V_{i} = 10\,V$ with a series resistance $R = 100\,\Omega$. In the given circuit,$R_{L}$ represents the variable load resistance. The ratio of the maximum and minimum value of $R_{L}$ is

$A$ potential divider circuit is connected to a $DC$ source of $20 \,V$, a light emitting diode $(LED)$ with a glow-in voltage of $1.8 \,V$, and a Zener diode with a breakdown voltage of $3.2 \,V$. The total length $(PR)$ of the resistive wire is $20 \,cm$. The minimum length of $PQ$ required for the $LED$ to just glow is ............. $cm$.