A zinc ball of radius 1 ,cm is charged to a p | vedclass

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(C) Given: Radius $R = 1 \,cm$,initial potential $V_{i} = -0.5 \,V$,wavelength of incident light $\lambda = 290 \,nm$,and threshold wavelength $\lambd

Vedclass · Accepted Answer

$0.54$

Vedclass · Answer

(C) Given: Radius $R = 1 \,cm$,initial potential $V_{i} = -0.5 \,V$,wavelength of incident light $\lambda = 290 \,nm$,and threshold wavelength $\lambda_{0} = 332 \,nm$. The work function of zinc is $\phi = \frac{hc}{\lambda_{0}} = \frac{1242 \,eV \cdot nm}{332 \,nm} \approx 3.74 \,eV$. The energy of the incident photon is $E = \frac{hc}{\lambda} = \frac{1242 \,eV \cdot nm}{290 \,nm} \approx 4.28 \,eV$. The maximum kinetic energy of the emitted photoelectrons is $K_{max} = E - \phi = 4.28 \,eV - 3.74 \,eV = 0.54 \,eV$. As electrons are emitted from the ball,the potential of the ball increases. The emission continues until the maximum kinetic energy of the emitted electrons becomes zero. Therefore,the final potential of the ball is $V_{f} = 0.54 \,V$.

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