Acceleration due to gravity on the moon is $\frac{1}{6}$ of the acceleration due to gravity on the earth. If the ratio of densities of earth $(\rho_e)$ and moon $(\rho_m)$ is $\frac{\rho_e}{\rho_m} = \frac{5}{3}$,then the radius of the moon $R_m$ in terms of $R_e$ will be:
- A$\frac{5}{18}R_e$
- B$\frac{1}{6}R_e$
- C$\frac{3}{18}R_e$
- D$\frac{1}{2\sqrt{3}}R_e$
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