The acceleration-time graph of a body is show | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) From the acceleration-time graph,we can observe three distinct phases of motion:$1$. In the first phase,the acceleration $a$ is constant and posit

Vedclass · Accepted Answer

Vedclass · Answer

(D) From the acceleration-time graph,we can observe three distinct phases of motion:$1$. In the first phase,the acceleration $a$ is constant and positive. Since $v = \int a \, dt$,the velocity increases linearly with time,represented by a straight line with a positive slope on a velocity-time graph.$2$. In the second phase,the acceleration $a = 0$. This means the velocity remains constant,represented by a horizontal line on a velocity-time graph.$3$. In the third phase,the acceleration $a$ is again constant and positive. This means the velocity increases linearly with time again,represented by a straight line with a positive slope.Comparing this with the given options,the graph that shows a linear increase in velocity,followed by a constant velocity,and then another linear increase is option $D$.

The acceleration-time graph of a body is shown. The corresponding velocity-time graph of the same body is

Similar Questions

From the $v-t$ graph,the

$A$ body is thrown vertically upwards. Which one of the following graphs correctly represents the velocity vs time?

The position $x$ of a particle with respect to time $t$ along the $x$-axis is given by $x = 9t^2 - t^3$,where $x$ is in metres and $t$ is in seconds. What will be the position of this particle when it achieves maximum speed along the $x$-direction?

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?

Vedclass Test Series

Exam Paper Generator

Online Exam Module