According to CIP rule,the correct arrangement | vedclass

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(B) According to the $CIP$ (Cahn-Ingold-Prelog) sequence rule,priority is assigned based on the atomic number of the atom directly attached to the chi

Vedclass · Accepted Answer

$-OH > -COOH > -CHO > -CH_2OH$

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(B) According to the $CIP$ (Cahn-Ingold-Prelog) sequence rule,priority is assigned based on the atomic number of the atom directly attached to the chiral center.$1$. Comparing the atoms directly attached: $-OH$ (Oxygen,$Z=8$) has the highest priority.$2$. For the carbon-containing groups: $-COOH$,$-CHO$,and $-CH_2OH$,we look at the atoms attached to the first carbon:- In $-COOH$,the carbon is bonded to $(O, O, O)$ (counting the double bond as two oxygens).- In $-CHO$,the carbon is bonded to $(O, O, H)$.- In $-CH_2OH$,the carbon is bonded to $(O, H, H)$.Comparing these sets,the priority order is $-COOH > -CHO > -CH_2OH$.Combining these,the overall order of decreasing priority is $-OH > -COOH > -CHO > -CH_2OH$.

According to $CIP$ rule,the correct arrangement in order of decreasing priority is

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