According to the Biot-Savart law,what is the | vedclass

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(C) According to the Biot-Savart law,the magnetic field $dB$ due to a current element $Idl$ at a point with position vector $r$ is given by $dB = \fra

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Zero

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(C) According to the Biot-Savart law,the magnetic field $dB$ due to a current element $Idl$ at a point with position vector $r$ is given by $dB = \frac{\mu_0}{4\pi} \frac{I(dl 	imes r)}{r^3}$.On the axis of the wire,the current element $dl$ and the position vector $r$ are collinear (i.e.,the angle $	heta$ between them is $0^\circ$ or $180^\circ$).Since the cross product $dl 	imes r = |dl||r| \sin(	heta)$,and $\sin(0^\circ) = 0$ or $\sin(180^\circ) = 0$,the magnetic field $dB$ becomes zero.Therefore,the magnetic field at any point on the axis of the wire is zero.

According to the Biot-Savart law,what is the magnetic field at a point on the axis of a current-carrying wire?

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