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(A) According to the kinetic theory of gases,the average kinetic energy of a gas molecule is given by $\frac{3}{2}kT$,where $k$ is the Boltzmann const

Vedclass · Accepted Answer

$1.5 \, RT$

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(A) According to the kinetic theory of gases,the average kinetic energy of a gas molecule is given by $\frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the absolute temperature.For one mole of gas,the total kinetic energy is obtained by multiplying the energy per molecule by the Avogadro number $(N_A)$:$E = N_A 	imes \frac{3}{2}kT = \frac{3}{2}(N_A k)T$.Since $N_A k = R$ (the universal gas constant),the energy per mole is $\frac{3}{2}RT$,which is equal to $1.5 \, RT$.

According to the kinetic theory of gases,the energy per mole of a gas is equal to:

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