According to the Bohr theory,which of the fol | vedclass

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(C) The energy of a photon emitted during an electronic transition is given by the formula: $E = \Delta E = 13.6 \ eV \left[ \frac{1}{n_1^2} - \frac{1

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$n = 6$ to $n = 5$

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(C) The energy of a photon emitted during an electronic transition is given by the formula: $E = \Delta E = 13.6 \ eV \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} ight]$.As the principal quantum number $n$ increases,the energy gap between consecutive shells decreases.The energy difference between shells $n$ and $n+1$ is given by $\Delta E = 13.6 \left[ \frac{1}{n^2} - \frac{1}{(n+1)^2} ight]$.Comparing the transitions:$(A)$ $n=6 	o n=1$: Large energy gap.$(B)$ $n=5 	o n=4$: $\Delta E \propto (1/16 - 1/25) = 0.0225$.$(C)$ $n=6 	o n=5$: $\Delta E \propto (1/25 - 1/36) = 0.0122$.$(D)$ $n=5 	o n=3$: $\Delta E \propto (1/9 - 1/25) = 0.0711$.The transition $n=6 	o n=5$ involves the shells with the highest principal quantum numbers,resulting in the smallest energy difference and thus the least energetic photon.

According to the Bohr theory,which of the following transitions in the hydrogen atom will give rise to the least energetic photon?

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