According to the Freundlich adsorption isothe | vedclass

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(D) The Freundlich adsorption isotherm is given by the equation $\frac{x}{m} = k \cdot p^{1/n}$ (where $n > 1$).At low pressure,the exponent $\frac{1}

Vedclass · Accepted Answer

All of the above are correct for different pressure ranges.

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(D) The Freundlich adsorption isotherm is given by the equation $\frac{x}{m} = k \cdot p^{1/n}$ (where $n > 1$).At low pressure,the exponent $\frac{1}{n} \approx 1$,so $\frac{x}{m} \propto p^1$.At high pressure,the exponent $\frac{1}{n} \approx 0$,so $\frac{x}{m} \propto p^0$.In the intermediate range,$\frac{x}{m} \propto p^{1/n}$.Since all these relations hold true for different pressure ranges,option $D$ is the correct answer.

According to the Freundlich adsorption isotherm,which of the following is correct?

Similar Questions

If $x$ gram of gas is adsorbed by $m$ gram of adsorbent at pressure $P$,the plot of $\log \frac{x}{m}$ versus $\log P$ is linear. The slope of the plot is: ($n$ and $k$ are constants and $n > 1$ )

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The Freundlich adsorption isotherm is given by:

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