(C) The average kinetic energy of gas molecules is given by the formula $KE_{avg} = \frac{3}{2} k_B T$, where $k_B$ is the Boltzmann constant and $T$

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Is directly proportional to the absolute temperature

(C) The average kinetic energy of gas molecules is given by the formula $KE_{avg} = \frac{3}{2} k_B T$, where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since $k_B$ is a constant, the average kinetic energy is directly proportional to the absolute temperature $T$.

Class 11 Chemistry States of Matter Kinetic molecular theory of gases and Molecular collisions

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According to the kinetic molecular theory of gases, the average kinetic energy of gas molecules:

MHT CET 2026 All MHT CET

A
Increases with increase in pressure
B
Decreases with increase in volume
C
Is directly proportional to the absolute temperature
D
Is the same for all gases at the same volume

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Kinetic molecular theory of gases and Molecular collisions

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At what temperature will the total kinetic energy of $0.30 \ mol$ of $He$ be the same as the total kinetic energy of $0.40 \ mol$ of $Ar$ at $400 \ K$ (in $K$)?

MediumAP EAMCET 2021

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Assertion $(A)$ At $300 \ K$, kinetic energy of $16 \ g$ of methane is equal to the kinetic energy of $32 \ g$ of oxygen.
Reason $(R)$ At constant temperature, kinetic energy of one mole of all gases is equal.

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At what temperature $T$ will the kinetic energy of $0.3 \ mol$ of $He$ be equal to the kinetic energy of $0.4 \ mol$ of $Ar$ at $400 \ K$ (in $K$)?

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What kind of forces exist between the molecules in an ideal gas?

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Which technique is commonly used to separate a mixture of two gases based on their rates of diffusion?

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According to the kinetic molecular theory of gases, the average kinetic energy of gas molecules:

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At what temperature will the total kinetic energy of $0.30 \ mol$ of $He$ be the same as the total kinetic energy of $0.40 \ mol$ of $Ar$ at $400 \ K$ (in $K$)?

Assertion $(A)$ At $300 \ K$, kinetic energy of $16 \ g$ of methane is equal to the kinetic energy of $32 \ g$ of oxygen.Reason $(R)$ At constant temperature, kinetic energy of one mole of all gases is equal.

At what temperature $T$ will the kinetic energy of $0.3 \ mol$ of $He$ be equal to the kinetic energy of $0.4 \ mol$ of $Ar$ at $400 \ K$ (in $K$)?

What kind of forces exist between the molecules in an ideal gas?

Which technique is commonly used to separate a mixture of two gases based on their rates of diffusion?

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Assertion $(A)$ At $300 \ K$, kinetic energy of $16 \ g$ of methane is equal to the kinetic energy of $32 \ g$ of oxygen.
Reason $(R)$ At constant temperature, kinetic energy of one mole of all gases is equal.