Acetic acid on heating with NH_3 forms A. Whe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Acetic acid $(CH_3COOH)$ reacts with $NH_3$ to form ammonium acetate,which upon heating undergoes dehydration to form acetamide $(A)$: $CH_3C

Vedclass · Accepted Answer

$CH_3CH_2NH_2, CH_3CH_2NC$

Vedclass · Answer

(B) $1$. Acetic acid $(CH_3COOH)$ reacts with $NH_3$ to form ammonium acetate,which upon heating undergoes dehydration to form acetamide $(A)$: $CH_3COOH + NH_3$ $\rightarrow CH_3COONH_4$ $\xrightarrow{\Delta} CH_3CONH_2 (A) + H_2O$.$2$. Acetamide $(A)$ is reduced by $LiAlH_4$ to form ethylamine $(B)$: $CH_3CONH_2 \xrightarrow{LiAlH_4} CH_3CH_2NH_2 (B)$.$3$. Ethylamine $(B)$ reacts with chloroform $(CHCl_3)$ in the presence of $KOH$ (Carbylamine reaction) to form ethyl isocyanide $(C)$: $CH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow CH_3CH_2NC (C) + 3KCl + 3H_2O$.$4$. Therefore,$B$ is $CH_3CH_2NH_2$ and $C$ is $CH_3CH_2NC$.

Acetic acid on heating with $NH_3$ forms $A$. When $A$ reacts with $LiAlH_4$ followed by hydrolysis,it gives $B$. When $B$ is heated with chloroform in $KOH$ medium,it gives $C$. What are $B$ and $C$ respectively?

Similar Questions

An organic compound $(C_3H_9N)$ $(A)$,when treated with nitrous acid,gave an alcohol and $N_2$ gas was evolved. $(A)$ on warming with $CHCl_3$ and caustic potash gave $(C)$ which on reduction gave isopropylmethylamine. Predict the structure of $(A)$.

$PhNH_2 + Ph_3COH \xrightarrow{H^{+}} P$ (major) (not an $N$-derivative). The product $(P)$ is:

Which of the following is most basic?

The order of basicity among the following compounds is:

In the following reaction,the reason why the meta-nitro product is also formed is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module