(A) The oxidation of primary alcohols with strong oxidizing agents like $KMnO_4$ or $K_2Cr_2O_7$ yields carboxylic acids with the same number of carbo

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(A) The oxidation of primary alcohols with strong oxidizing agents like $KMnO_4$ or $K_2Cr_2O_7$ yields carboxylic acids with the same number of carbon atoms. Ethanol $(C_2H_5OH)$ contains two carbon atoms. Upon oxidation,it forms acetic acid $(CH_3COOH)$,which also contains two carbon atoms. The reaction is: $C_2H_5OH + 2[O] \xrightarrow{Oxidation} CH_3COOH + H_2O$.