Addition of $H_{2}SO_{4}$ to $BaO_{2}$ produces

  • A
    $BaO, SO_{2}$ and $H_{2}O$
  • B
    $BaHSO_{4}$ and $O_{2}$
  • C
    $BaSO_{4}, H_{2}$ and $O_{2}$
  • D
    $BaSO_{4}$ and $H_{2}O_{2}$

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In $H_2O_2$,the two oxygen atoms are connected by:

Electrolysis of $X$ gives $Y$ at anode. Vacuum distillation of $Y$ gives $H_2O_2$. The number of peroxy $(O-O)$ bonds present in $X$ and $Y$ respectively are :

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