Affinity for hydrogen decreases in the group | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) As the size of the halogen atom increases from $F$ to $I$,the $H-X$ bond length in halogen acids also increases from $HF$ to $HI$.Bond length orde

Vedclass · Accepted Answer

$HF$

Vedclass · Answer

(A) As the size of the halogen atom increases from $F$ to $I$,the $H-X$ bond length in halogen acids also increases from $HF$ to $HI$.Bond length order: $HF Due to the increase in bond length,the strength of the $H-X$ bond decreases from $HF$ to $HI$.Consequently,the bond dissociation enthalpy decreases from $HF$ to $HI$.The order of $H-X$ bond dissociation enthalpy $(kJ/mol)$ is: $HF (574.0) > HCl (428.1) > HBr (362.5) > HI (294)$.Therefore,$HF$ has the highest bond dissociation enthalpy.

Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have the highest bond dissociation enthalpy?

Similar Questions

$Br_2 + NaOH \xrightarrow{R.T.} Y + Z$
If $Y$ gives a precipitate with $AgNO_3$,then $Z$ does not undergo a reaction with:

Which of the following reactions would be incorrect?

Identify the correct decreasing order of boiling point for hydrides of halogens.

Unlike other halogens,fluorine does not show higher oxidation states because:

When $1 \ mol$ of fluorine reacts with $2 \ mol$ of hot and concentrated $KOH$,the products obtained are $KF$,$H_2O$,and $O_2$. The molar ratio of $KF$,$H_2O$,and $O_2$ produced is respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module