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(D) Let the sum of the ages of the five members be $S$. The average age is $S/5$.After $3$ years,the sum of the ages of the same five members would ha

Vedclass · Accepted Answer

$15$

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(D) Let the sum of the ages of the five members be $S$. The average age is $S/5$.After $3$ years,the sum of the ages of the same five members would have been $S + (5 	imes 3) = S + 15$.Let the age of the replaced member be $x$ and the new member be $y$.The new sum of ages is $S - x + y$.According to the problem,the new average is equal to the average $3$ years ago,which is $(S/5) - 3$.So,$(S - x + y) / 5 = (S/5) - 3$.Multiplying by $5$,we get $S - x + y = S - 15$.Therefore,$x - y = 15$.The difference between the ages of the replaced and the new member is $15$ years.

After replacing an old member by a new member,it was found that the average age of five members of a club is the same as it was $3$ years ago. The difference between the ages of the replaced and the new member is (in years):

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