Air entering the lungs ends up in tiny sacs c | vedclass

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(D) $1$. Calculate the volume of the alveolus $(V)$: $V = \frac{4}{3} \pi r^3 = \frac{4}{3} 	imes 3.14 	imes (0.0050 \ cm)^3 = 5.236 	imes 10^{-7}

Vedclass · Accepted Answer

$1.7 	imes 10^{12}$

Vedclass · Answer

(D) $1$. Calculate the volume of the alveolus $(V)$: $V = \frac{4}{3} \pi r^3 = \frac{4}{3} 	imes 3.14 	imes (0.0050 \ cm)^3 = 5.236 	imes 10^{-7} \ cm^3 = 5.236 	imes 10^{-13} \ m^3 = 5.236 	imes 10^{-10} \ L$.$2$. Use the ideal gas law $(PV = nRT)$ to find the total moles of air $(n_{air})$: $n_{air} = \frac{PV}{RT} = \frac{1.0 \ atm 	imes 5.236 	imes 10^{-10} \ L}{0.0821 \ L \cdot atm \cdot K^{-1} \cdot mol^{-1} 	imes 310 \ K} = 2.057 	imes 10^{-11} \ mol$.$3$. Calculate the moles of oxygen $(n_{O_2})$: $n_{O_2} = 0.14 	imes n_{air} = 0.14 	imes 2.057 	imes 10^{-11} = 2.88 	imes 10^{-12} \ mol$.$4$. Calculate the number of oxygen molecules $(N)$: $N = n_{O_2} 	imes N_A = 2.88 	imes 10^{-12} 	imes 6.022 	imes 10^{23} \approx 1.73 	imes 10^{12}$ molecules.

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