All bonds in benzene are equal due to

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(C) The correct answer is $(C)$.In benzene,the delocalization of $\pi$-electrons occurs due to resonance.This delocalization makes all the carbon-carb

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Resonance

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(C) The correct answer is $(C)$.In benzene,the delocalization of $\pi$-electrons occurs due to resonance.This delocalization makes all the carbon-carbon $(C-C)$ bonds equivalent.The observed $C-C$ bond length in benzene is $1.39 \ \mathring{A}$,which is intermediate between the single $C-C$ bond length $(1.54 \ \mathring{A})$ and the double $C=C$ bond length $(1.34 \ \mathring{A})$.

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