All the diodes are ideal. The current flowing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the given circuit,the diodes $D_1$ and $D_2$ are in forward bias because their $p$-terminals are connected to the positive terminal of the batt

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) In the given circuit,the diodes $D_1$ and $D_2$ are in forward bias because their $p$-terminals are connected to the positive terminal of the battery through the $1 \, \Omega$ resistor and their $n$-terminals are connected to the negative terminal.The diodes $D_3$ and $D_4$ are in reverse bias because their $p$-terminals are connected to the negative terminal of the battery,so they act as open circuits.The equivalent resistance of the upper branch (containing $D_1$ and $D_2$) is $R_{up} = 1 \, \Omega + 2 \, \Omega + 1 \, \Omega = 4 \, \Omega$.The middle branch has a resistance of $4 \, \Omega$.These two branches are in parallel,so their equivalent resistance is $R_p = \frac{4 \, \Omega 	imes 4 \, \Omega}{4 \, \Omega + 4 \, \Omega} = 2 \, \Omega$.The total resistance of the circuit including the internal $3 \, \Omega$ resistor is $R_{total} = 2 \, \Omega + 3 \, \Omega = 5 \, \Omega$.The total current from the battery is $I = \frac{V}{R_{total}} = \frac{10 \, V}{5 \, \Omega} = 2 \, A$.Since the resistance of the upper branch and the middle branch are equal ($4 \, \Omega$ each),the current $I$ divides equally between them.Therefore,the current flowing through the $2 \, \Omega$ resistor is $I_{up} = \frac{I}{2} = \frac{2 \, A}{2} = 1 \, A$.

All the diodes are ideal. The current flowing in the $2 \, \Omega$ resistor connected between the diodes $D_1$ and $D_2$ is .......... $A$

Similar Questions

The 'Golden Rice' variety is enriched with which of the following?

'Amoebiasis' (amoebic dysentery) is caused by

If $l$ and $m$ are the degree and the order respectively of the differential equation of the family of all circles in the $XY$ plane with radius $5$ units,then $2l + 3m =$

The moment of inertia of a uniform annular disc of internal radius $r$,external radius $R$,and mass $M$ about an axis passing through its center and perpendicular to its plane is:

$50 \ mL$ of $H_2O$ is added to $50 \ mL$ of $1 \times 10^{-3} \ M$ barium hydroxide solution. What is the $pH$ of the resulting solution?

Vedclass Test Series

Exam Paper Generator

Online Exam Module