Allyl phenyl ether can be prepared by heating | vedclass

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Question

(B) is the correct option. Allyl phenyl ether is prepared by the $Williamson$ ether synthesis. In this reaction,sodium phenoxide $(C_6H_5-ONa)$ acts a

Vedclass · Accepted Answer

$CH_2=CH-CH_2-Br + C_6H_5-ONa$

Vedclass · Answer

(B) is the correct option. Allyl phenyl ether is prepared by the $Williamson$ ether synthesis. In this reaction,sodium phenoxide $(C_6H_5-ONa)$ acts as a nucleophile and attacks the electrophilic carbon of allyl bromide $(CH_2=CH-CH_2-Br)$ via an $S_N2$ mechanism. Aryl halides like bromobenzene $(C_6H_5-Br)$ do not undergo nucleophilic substitution under ordinary conditions due to the partial double bond character of the $C-X$ bond. Reaction: $C_6H_5-ONa + Br-CH_2-CH=CH_2 \rightarrow C_6H_5-O-CH_2-CH=CH_2 + NaBr$

Allyl phenyl ether can be prepared by heating:

Similar Questions

The products formed during the following reaction are:
$(CH_{3})_{3}C-O-CH_{3} + HI \rightarrow ?$

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$I$: Tetrahydropyran
$II$: Isochroman (or similar cyclic ether fused to benzene)
Which forms a di-iodide on reaction with $HI$ (excess)?

For the reaction shown below,identify products $A$ and $B$ $:$

In the given reaction,the product is:
$C_6H_5OH + C_2H_5I \xrightarrow{C_2H_5O^- / C_2H_5OH} \text{Product}$

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