Although carbon and hydrogen are better reducing agents,they are not used to reduce metallic oxides at high temperatures. Why?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) This is due to the formation of metal carbides and metal hydrides at high temperatures.
$CaO + 3C \xrightarrow{2273 \ K} CaC_2 + CO$
$Ca + H_2 \rightarrow CaH_2$

Explore More

Similar Questions

Which oxide formation according to the Ellingham diagram shows a graph with a sudden change in slope?

The metal extracted by the electrolysis of its fused salt is

Limestone is present in the blast furnace production of iron in order to
$(I)$ provide a source of $CaO$
$(II)$ remove some impurities
$(III)$ supply $CO_2$

The incorrect statement about the Hall$-$Heroult process is:

Which of the following statements is not correct?
$1$. Reduction of alumina to give aluminium by magnesium is thermodynamically feasible.
$2$. The point of intersection of $Al_2O_3$ and $MgO$ curves in Ellingham diagram is below $1665 \ K$.
$3$. Use of magnesium as reducing agent in metallurgy of aluminium is economical.
$4$. Ellingham diagram represents the graphical plot of Gibbs energy vs temperature for the formation of the oxides of common metals and reducing agents.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo