Aluminum dissolves in mineral acids and aqueous alkalis and thus shows amphoteric character. $A$ piece of aluminum foil is treated with dilute hydrochloric acid or dilute sodium hydroxide solution in a test tube and on bringing a burning match stick near the mouth of the test tube,a pop sound indicates the evolution of hydrogen gas. The same activity when performed with concentrated nitric acid,the reaction does not proceed. Explain the reason.

(N/A) Aluminum is amphoteric in nature; it reacts with acids and bases to produce salt and $H_{2}$ gas. The evolution of $H_{2}$ gas is confirmed by the pop sound produced when a burning matchstick is brought near the mouth of the test tube.
$2 Al(s) + 6 HCl(aq) \rightarrow 2 AlCl_{3}(aq) + 3 H_{2}(g)$
$2 Al(s) + 2 NaOH(aq) + 6 H_{2}O(l) \rightarrow 2 Na[Al(OH)_{4}](aq) + 3 H_{2}(g)$
When $Al$ reacts with concentrated $HNO_{3}$,a thin,non-porous,and inert layer of aluminum oxide $(Al_{2}O_{3})$ forms on the surface of the metal. This layer acts as a protective barrier,preventing further reaction between the metal and the acid,a phenomenon known as passivation.